p^2-20p+12=-7

Solution for p^2-20p+12=-7 equation:

p^2-20p+12=-7

We move all terms to the left:

p^2-20p+12-(-7)=0

We add all the numbers together, and all the variables

p^2-20p+19=0

a = 1; b = -20; c = +19;
Δ = b2-4ac
Δ = -202-4·1·19
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-18}{2*1}=\frac{2}{2}
=1
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+18}{2*1}=\frac{38}{2}
=19
$